いやなブログ: 配列操作の比較表: Ruby, Python, JavaScript, Perl, C++

の AppleScript 版
HyperCard はふざけた丈け (配列が存在しない――単なる文字列)

Ruby (Array)	AppleScript (List)	HyperCard (Items)
a = [1, 2, 3]	set a to {1, 2, 3} copy {1, 2, 3} to a {1, 2, 3} returning a	put "1,2,3" into a
a.length	length of a a's length count every item of a count a's every item count items of a count a's items number of every item of a number of a's every item number of items of a number of a's items	the number of items of a
a.empty?	a = {}	a is empty
a.push(x)	set end of a to x set a's end to x copy x to end of a copy x to a's end x returning end of a x returning a's end	put the itemDelimiter & x after a put x after item (1 + the number of items of a) of a
a.unshift(x)	set front of a to x set a's front to x copy x to front of a copy x to a's front x returning front of a x returning a's front	put x & the itemDelimiter before a
a.pop	function が必要 on pop(L) if L's contents's length = 0 then return {} copy L's contents's last item to popItem copy L's contents's items 1 thru -2 to L's contents return popItem end pop pop(a reference to a)	2 文に分けて get last item of a delete last item of a
a.shift	function が必要 on shift(L) if L's contents's length = 0 then return {} copy L's contents's first item to shiftItem copy L's contents's rest to L's contents return shiftItem end shift shift(a reference to a)	2 文に分けて get first item of a delete first item of a
a.concat(b)	set a to a & b copy a & b to a a & b returning a	put the itemDelimiter & b after a put b after item (1 + the number of items of a) of a
a.clear	set a to {} copy {} to a {} returning a	put empty into a
a.insert(i, x)	set a to items 1 thru (i - 1) of a & x & items i thru end of a copy items 1 thru (i - 1) of a & x & items i thru end of a to a items 1 thru (i - 1) of a & x & items i thru end of a returning a	put x & the itemDelimiter before item i of a
a.delete(x)	function が必要 on deleteitem of x from r set temp to {} repeat with i in r's contents get i as item if result is not x then set temp's end to result end repeat set r's contents to temp end deleteitem deleteitem of x from a reference to a	delete item (the number of items of char 1 to offset(the itemDelimiter & x & the itemDelimiter, the itemDelimiter & a & the itemDelimiter) - 1) of a of a
a.delete_at(i)	set a to items 1 thru (i - 1) of a & items (i + 1) thru end of a copy items 1 thru (i - 1) of a & items (i + 1) thru end of a to a items 1 thru (i - 1) of a & items (i + 1) thru end of a returning a	delete item i of a
a.include?(x)	x is in a	offset(the itemDelimiter & x & the itemDelimiter, the itemDelimiter & a & the itemDelimiter) is not 0
a.index(x)		the number of items of char 1 to offset(the itemDelimiter & x & the itemDelimiter, the itemDelimiter & a & the itemDelimiter)
a.first	first item of a a's first item 1st item of a a's 1st item item 1 of a a's item 1	first item of a item one of a item 1 of a
a.last a[-1]	last item of a a's last item item -1 of a a's item -1	last item of a
a[i,l] a.slice(i, l)	items i thru (i + l) of a a's items i thru (i + l)	item i to i+l of a
a[i..j] a.slice(i..j)	items i thru j of a a's items i thru j	item i to j of a
a[i...j] a.slice(i...j)	items i thru (j - 1) of a a's items i thru (j - 1)	item i to j-1 of a
a.sort!		sort items of a
a.each { |x| ... }	repeat with x in a ... end repeat	repeat with i = 1 to the nmber of items of a put item i of a into x ... end repeat